Hello and thanks for being so patient :smile:
But I'd have to look at whether the points lie on the axes? But they do, don't they? In which case wouldn't r= 0? :confused:
How can I use these position vectors to help me? I thought the vector r was r and could just be substituted into the...
Thanks; I was looking for that!
I've tried to work it out like this: mi12 + 02m2= x ; mi22 + 12m2=y ; mi32 + 02m2= z
I came up with the coordinates 1,6,9. Is this okay?
I'm going to work on that question last because I'm still somewhat confused...the parallel axis theorem is ( I think)...
Alright well I know that the moment of inertia depends on the axis in terms of location...and I think it has something to do with rotational motion like kinetic energy. In my textbook it says the definition of moment of inertia is ∑ mi ri ^2. I also know that there's different moments of inertia...
Could someone help me get started on these two types of problems? (In terms of what equations to use/what the problems are asking for or mean)
Moments of inertia
-A rigid body consists of 2 point masses m1= 1kg at a position vector r1= (1,2,3) m and m2 = 2kg at a position vector r2- (0,1,0)...
Thank you. I was able to get the problem done correctly :smile:
I have two other problems that I need help getting started on:
Moments of inertia
-A rigid body consists of 2 point masses m1= 1kg at a position vector r1= (1,2,3) m and m2 = 2kg at a position vector r2- (0,1,0) m. Calculate...
Problem:
At the Large Hadron Collider, two beams of protons collide head-on. Each beam has a speed of .700c relative to the earth. What is the magnitude of the velocity of one beam of protons relative to the other one?
>>I have no idea what equations to use :frown:
>>I could really use...
Homework Statement
"Blocks A, B, and C are placed as in the figure and connected by ropes of neligible mass. Both A and B weigh 25.0 N each, and the coefficient of kinetic friction between each block and the surface is 0.35. Block C descends with constant velocity. a) Draw separate free body...