Recent content by raymondmorrow

Heat lost by mutual: (0.08kg)(900 j/kg*C)(30C-T) =72 J/C(30C-T) Ice to melt: Q=(M ice)(lf) =(0.05)(3.33x10^5) =16650J 0.05kg * 0.2kg = 0.25kg heat gained by water from ice: (16650) + (0.25)(4.19 x 10 ^ 3)(T-0C) 16650+1047.5(T--0C) 16650+1047.5T 72 J/C(30C-T)=16650+1047.5T...

heat lost by metal= M metal*C metal*change in temperature heat gained by ice-water= (Q ice + Q water)+ m water*C water* change in temperature heat lost by metal= heat gained by ice-water I keep trying but I can't get the right answer (9.5 Celcius) Any help is very appreciated.

Homework Statement A 50-g of ice, initially at 0.0C, is dropped into 200 g of water in an 80-g aluminum container, both initially at 30C. What is the final equilibrium temperature? (Specific heat for aluminum is 900 J/Kg*C, the specific heat of water is 4186 J/Kg*C, and...