Recent content by rbmwz1

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    Solving Curve Function: Intercepts, Parabola Help

    Hey, I hope this helps, I integrated your function. Integrate (-1/16x^2 +1), from -4,4. = -1/48x^3+x, from -4, 4. So. [(-1/48)(4^3)+4]-[(-1/48)(-4^3) - 4] = [-4/3 +4 ] - [4/3 -4] = 8-(8/3) = 16/3 This should give you the area under the graph from -4 --> 4 hope this works...
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