Recent content by rdhc1330

I have a quick question, how do you calculate Collector emitter resistance?

Aha! Awesome, I understand this so clearly now. When I realized what I was doing with the voltage it became so clear! Thanks a lot Zryn, so very very much!

hey wait, can't I just go 6.2 / 80? 0.078A if we do 6.2/90 = 0.069A 6.2/80 = 0.078A 6.2/70 = 0.089A 6.2/60 = 0.103A == 0.339A

so --> (90*70*60 / 90 + 70 + 60) ------------------------------- (90*70*60 / 90 + 70 + 60) + 80

how about... (R3*R5*R6 / R3+R5+R6) / (R3*R4*R5*R6 / R3+R4+R5+R6) * 0.337 = 0.006A

Oh snap, 1 / (1/90 + 1/70 + 1/60)

ok yes - but r3 + r5 + r6 = 220 + r4 (80) = 300? or am I looking at it wrong? do you mean the 18.33?

so it should be = 220/300 * 0.337

I'm actually confused now...

Ir4 = (Rt/R4) * It Ir3 = (35.48/90) * 0.338 = 0.133A Ir5 = 0.171A Ir6 = 0.200A

ok so I got (35.56/80) * 0.337 = 0.15A

alright I'll check the math on that and then let you know what I get for the final answer for the current through R4... Hold tight

Isn't the voltage drop the same across all resistors in parallel? While the current is split also sorry: Rt(R1) = 1/ (1/30 + 1/40)

I'm going to take a stab at this and say = 80/300 * 18.32ohms = 4.89ohms (resistance segment of R4) then using ohms law --> 6.18/4.89 = 1.26A ? Am I on the right track?

awesome, that helped, so I have now figured out that across R1 (R1 + R2) that it is 17.24Ohms and R2 (R3 + R4 + R5 + R6) is 18.32Ohms, then used the voltage divider equation Vin * R1/R1+R2 to find that R1 = 5.82V and R2 = 6.18V. Now I'm confused about what to do next?