Recent content by realslow

okay I realized I just need to use Fg = mg :)

Sorry about that.. Fe = QE

I know that Fe = Q\Sigma so if I find Fg I can solve for Q. However, I am confused as to what values I use for Fg. I know the gravitational constant and the two masses (which are equal?), but am confused about the distance between them. Should I be using the radius of the drop or twice the radius?

Sorry about the electric field equations.. they came out weird haha

Homework Statement Find the charge on the oil drop in Coulombs, and the number of electrons it is "missing". Vplates= 2400 V Dplates = 0.020 m Oil Density = 850 kg/m3 Oil Drop Radius = .000051 m (from Stokes’ Law) Homework Equations E = V/d Volume = 4/3πr3 m= density x volume...

Yes, I do :) So I guess my vectors reasoning was pretty accurate then! Thank you soooo much for your help!

Ahh thank you so much! Many many thanks :D I finally got the correct answer! However, I would really appreciate it if you could explain why the three forces made a triangle :) I'm thinking along the lines of vectors, but I'm not too sure..

It's not going so well :( this question is really making me depressed *sighs* I tried getting the angle, but I can't. I've tried getting two equations for the unknown angle, but I only ended up with one, so.. I'm at a dead end.

Alright, I will try once again! Thanks for the help :) Good night!

Oh I guess so, I just noticed your diagram hehe sorry :)

I know tension force is for sure, but isn't gravity working on it as well?

Fapp would be Fgsinθ The forces I drew were FT, Fapp, Fg and FN Maybe I'm not drawing the diagram right :( should I have two separate diagrams for horizontal and vertical? Because I'm only drawing one...

Okay, I will consider that, thanks! I'm really having trouble with this question.. For the horizontal component, does FC = FT - Fapp in this case?

Would the net force of the vertical component be 0?

Okay, thank you, I will try the question again!