Recent content by Rectification
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Newton's Second Law - Polar Coordinates
Thank you so much for the help! I truly appreciate it :)- Rectification
- Post #7
- Forum: Introductory Physics Homework Help
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Newton's Second Law - Polar Coordinates
Alright so I think I finally have an answer! So my new force equations are: These forces act perpendicular to each other, so to find the net force of interaction you can use the Pythagorean Theorem. And like you said, the force of friction This gives me the equation Now all that was...- Rectification
- Post #5
- Forum: Introductory Physics Homework Help
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Newton's Second Law - Polar Coordinates
I'm not too sure how I would incorporate the weight in the force equation though. All I can really think of doing is: However this seems a bit strange to me because I can't see how the weight of the object would contribute to the forces in the direction of theta Also, I haven't used the fact...- Rectification
- Post #3
- Forum: Introductory Physics Homework Help
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Newton's Second Law - Polar Coordinates
Homework Statement Given that: theta_dot = 6 rad/sec m_A = 0.8kg u_k = 0.40 The problem also mentions that movement is at a constant angular rate so I think that means: r_doubleDot = 0 theta_doubleDot = 0 Lastly, at an instant: r_dot = 800mm/sec = 0.8m/sec 2. Homework Equations...- Rectification
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- Coordinates Law Newton Newton's second law Polar Polar coordinates Second law
- Replies: 6
- Forum: Introductory Physics Homework Help