thank you for the answer but i have another problem.
i tried 2 different ways but i don't know which one is right.
first method: polar coordinate conversion.
3x= r cos (theta), 2y = r sin (theata) 0 < r < 6 , 0 < theta < 2 pi
so ∫∫ r^2 (cos(theta))^2 r dr d(theta)
= 36 pi...
∫∫ x^2 dA ; bounded by ellipse; which soln is right?
Homework Statement
the problem is:
try ∫∫ x^2 dA ; bounded by ellipse 9x^2+4y^2=36
and i tried 2 different ways but i don't know which one is right.
Homework Equations
The Attempt at a Solution
first method: polar...
Homework Statement
try ∫∫G x^2 dA ;value is the region bounded by the ellipse 9x^2+4y^2=36
Homework Equations
The Attempt at a Solution
i think i have to change the variables to polar coordinate or U,V function but i have no idea.