Recent content by red6290

thank you very much it was really helpful!

thank you for the answer but i have another problem. i tried 2 different ways but i don't know which one is right. first method: polar coordinate conversion. 3x= r cos (theta), 2y = r sin (theata) 0 < r < 6 , 0 < theta < 2 pi so ∫∫ r^2 (cos(theta))^2 r dr d(theta) = 36 pi...

∫∫ x^2 dA ; bounded by ellipse; which soln is right? Homework Statement the problem is: try ∫∫ x^2 dA ; bounded by ellipse 9x^2+4y^2=36 and i tried 2 different ways but i don't know which one is right. Homework Equations The Attempt at a Solution first method: polar...

Homework Statement try ∫∫G x^2 dA ;value is the region bounded by the ellipse 9x^2+4y^2=36 Homework Equations The Attempt at a Solution i think i have to change the variables to polar coordinate or U,V function but i have no idea.