Recent content by RedBarchetta

Homework Statement A capacitor is charged until it holds 5.0 J of energy. It is then connected across a 10-k\Omega resistor. In 8.6 ms, the resistor dissipates 2.0 J. What is the capacitance? Homework Equations Q=CV U=(1/2)CV^{2} The Attempt at a Solution I'm not quite sure what...

Well, I'm assuming you're a math major if you're taking a course for math majors! :smile: If you've taught yourself Calculus from Apostol, had success in Calculus III, and do well in Linear Algebra, then I doubt Differential Equations or an intro proof/logic class will cause too much stress...

Homework Statement Describe the composition and temperature of the equilibrium mixture after 1.0 kg of ice at -40*C is added to 1.0 kg of water at 5.0*C.Homework Equations \begin{gathered} Q = mc\Delta T \hfill \\ Q = mL \hfill \\ \end{gathered} Book answer:1.2kg ice, 0.80 kg water...

Thanks Coto. I had a feeling that the part a solution key was incorrect.

Yes. Then you are taking the square root of 2gh to get v. :smile:

This is a conservation problem. Choose the bottom of the hill as h=0. This will make solving for the unknown easy, even though you can choose h=0 at the top if you wish. So, initially the car is at rest, so it has zero kinetic energy. Since I took h=0 at the bottom, the car has gravitational...

Homework Statement Write expressions for simple harmonic motion (a) with amplitude 10 cm, frequency 5.0 Hz, and maximum displacement at t=0; and (b) with amplitude 2.5 cm, angular frequency 5.0 1/s, and maximum velocity at t=0.Homework Equations \begin{gathered} x(t) = A\cos (\omega t +...

Homework Statement http://img206.imageshack.us/img206/8178/ladderjt1.png A uniform 5.0-kg ladder is leaning against a frictionless vertical wall, with which it makes a 15* angle. The coefficient of friction between ladder and ground is 0.26. Can a 65-kg person climb to the top of the ladder...

Any recommendation's for a good textbook to study analysis solo? I know that there is Rudin & Apostol, although I'm sure there more "user friendly" introductory books. I was thinking about picking up baby Rudin to attempt the material. Since I'm going to be taking Calculus III(vector) next...

Part 4: Alright, now just solving the integral: \begin{gathered} \int {\frac{{2s + 2}} {{(s^2 + 1)(s - 1)^3 }}} = \frac{1} {2}\int {\frac{{ds}} {{s^2 + 1}} - \frac{1} {2}\int {\frac{{s ds}} {{s^2 + 1}}} + \int {\frac{{1/2}} {{s - 1}}ds - } } \int {\frac{{ds}} {{(s - 1)^2 }} + \int...

Part 3: \begin{gathered} \int {\frac{{2s + 2}} {{(s^2 + 1)(s - 1)^3 }}} = \int {\left[ {\frac{{As + B}} {{s^2 + 1}} + \frac{C} {{s - 1}} + \frac{D} {{(s - 1)^2 }} + \frac{E} {{(s - 1)^3 }}} \right]} ds \hfill \\ \int {\frac{{2s + 2}} {{(s^2 + 1)(s - 1)^3 }}} = \int {\left[...

Part 2: Now find the coefficients. I suppose you can use a calculator if you want to check for these. :smile: \begin{gathered} s^4 :A + C = 0 \hfill \\ s^3 :B - 3A - 2C + D = 0 \hfill \\ s^2 :3A - 3B + 2C - D = 0 \hfill \\ s^1 :3B - A - 2C + D = 2 \hfill \\ s^0 :C - B - D...

Homework Statement \int {\frac{{2s + 2}} {{(s^2 + 1)(s - 1)^3 }}ds} The Attempt at a Solution This is a long one...First, I split the integrand into partial fractions and find the coefficients: \begin{gathered} \frac{{2s + 2}} {{(s^2 + 1)(s - 1)^3 }} = \frac{{As + B}}...

Homework Statement \int {\frac{{2s + 2}} {{(s^2 + 1)(s - 1)^3 }}ds} The Attempt at a Solution This is a long one...First, I split the integrand into partial fractions and find the coefficients: \begin{gathered} \frac{{2s + 2}} {{(s^2 + 1)(s - 1)^3 }} = \frac{{As + B}}...

You're right. :smile: It just took me a while to notice that. It definitely decreases the difficulty level. Thanks.