Alrighty then, and for your example in the previous post I would do the same but for the ##x## axis. And the vector ##n## would be like a position vector stemming from the origin point of the First Reference Frame, along which the "boost" is occurring.
I think I get it now.
Many, many thanks...
I see. How would this ##R^{~}## matrix look like? I've only been introduced to the classical rotation matrix:
Also does the empty space left in the matrix ##R## mean that those quadrants are occupated only by zeroes?
And would I need something like this
##x = \gamma^{-1}_x x'##
(where ##\gamma_x = \gamma(\vec v\cdot \hat x)##)
for every axis ?
Or could I use the same ##\gamma## for all axes?
Thank you for your input, @ergospherical @weirdoguy and @A.T. .
I would also want to know if knowing the Lorentz Transformation for Time in the Second Reference Frame would help me in transforming the trajectory of an object bouncing in the second frame to the first one.
Like this: I have an...
Been studying Special Relativity in Uni. and I've noticed that all examples of relativistic motion provided are motions only along a single axis, like the one below:
The particle's Reference Frame is moving only along the X axis in the example above.
In this case the Lorentz Transformation for...