THANK YOU SO SO MUCH! it was right! I see where the other guy was trying to guide me too, which makes a lot more sense NOW! Sorry this had to have been really frustrating for you. I'm a bit slow at times (especially when it comes to physics)
ahhh .172, yeah that had to have just been a finger slip probably hit like .804 rather than .904. if this is right and works I will be naming my first child Gneili
ok so I'm looking for my I2 if 2.087A is my I value then I need to put the resistor values into the R2/R2+R1 part of the equation.
I'm sorry dude I'm really trying I promise I am I really appreciate the patience, there's no reason this should be taking you this long.
is it just...
that's where I'm starting to get confused. so if my current through the top half from a to B is 2.089(yes 8V/R is how I arrived at that.) but that's the current through 2 resistors, so I can't use that as my I value?
no that's just finding the current going through the bottom half of my bigger part of the resistor and I have to find the current through R2 so I would have to take that current and then do the same process over?
and that I just had to sum up the resistance and then do EXACTLY what I did on the previous problem and for some reason it's been the most difficult thing in the world for me?
yeah I rounded up to 2.1 but 2.089 I think was may actual value. the second path the one we're working on has a 3.3 ohm resistor then two broken into parallel resistors of 4 and 17ohms. for the first path it's just a series of a 2 and 3 ohm resistor.
ok that doesn't work either? wait I'm missing something? because your equations only have 2 resistors and I need to include 3 resistors? but if I'm adding resistance shouldn't it be 3.3 + (1/17+1/4)^-1?