Recent content by Rhythmer
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Radical simplification question
HINT: \sqrt{9x^2-6x+1} = \sqrt{9x^2-(3+3)x+1} = \sqrt{9x^2-3x-3x+1} Try to complete it yourself.- Rhythmer
- Post #8
- Forum: Precalculus Mathematics Homework Help
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Question 21 - Final question on higher paper
It is. You're right.- Rhythmer
- Post #14
- Forum: Precalculus Mathematics Homework Help
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How Do You Simplify (cos(2x))^2 Using Trigonometric Identities?
Doesn't (cos(2x))2 = cos2(2x)2 = cos2(4x2) ?- Rhythmer
- Post #4
- Forum: Precalculus Mathematics Homework Help
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High School Easy Questions, Difficult Answers
I mean I was trying to be "neutral" and not biased against people who don't believe 1 is not a prime, etc.- Rhythmer
- Post #18
- Forum: Linear and Abstract Algebra
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Undergrad Intermediate Value Theorem for Polynomials
I need to prove the IVT. Our professor told us there is such proof but it's not an easy one.- Rhythmer
- Post #3
- Forum: Linear and Abstract Algebra
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High School Easy Questions, Difficult Answers
Well guys I'd like to emphasize that my purpose of this thread is just as I said before. I'm not attempting to redefine the factorial of 0 or to let 1 be a prime but what I'm trying to do is to discuss the topic with 'neutrality'. I do think all of you are right and I'm convinced to all of...- Rhythmer
- Post #16
- Forum: Linear and Abstract Algebra
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Step-by-Step Solution for Solving Exponential Equations with Fractional Bases
(\frac{1}{9})^m = 81^{m+4} (9^{-1})^m = (9^2)^{m+4} (9)^{-m} = (9)^{2m+8} -m = 2m+8 -8 = 3m m = - \frac{8}{3}- Rhythmer
- Post #3
- Forum: Precalculus Mathematics Homework Help
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High School Easy Questions, Difficult Answers
I think a prime number is a number that has no factors other than itself and 1 People are not to decide whether a prime number itself can be 1 Could you give us any example of a case where 1 must not be a prime number?- Rhythmer
- Post #12
- Forum: Linear and Abstract Algebra
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Undergrad Intermediate Value Theorem for Polynomials
Prove: if P is a polynomial function and P(a) and P(b) have opposite signs, then there exists at least one value c between a and b for which P(c) = 0- Rhythmer
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- Polynomials Theorem Value
- Replies: 3
- Forum: Linear and Abstract Algebra
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High School Easy Questions, Difficult Answers
However, the definition n!=n(n-1)(n-2)…3.2.1 means the factorial of any non-negative integer, n, is the product of n and all integers we obtain by decrementing n continuously by 1; and we would stop decrementing when number 1 is reached. Therefore, for any value of n, (n-1) cannot be < 1...- Rhythmer
- Post #3
- Forum: Linear and Abstract Algebra
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High School Easy Questions, Difficult Answers
Hi. I know the following two questions might seem stupid, but I really need the correct answers in order to better understand the way we deal with numbers. 1. How can we prove that (0! = 1)? We all know (4! = 4*3*2*1), (3! = 3*2*1), (2! = 2*1), (1! = 1) But for 0, (0! = 1) doesn't make...- Rhythmer
- Thread
- Replies: 18
- Forum: Linear and Abstract Algebra
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Graduate A Question to Trouble Even the Best of You
For all terms in the sequence: X_n = X_{n-1} + ( (n-1) * 10 ) Starting from (n = 1), X_0 = 1 :rolleyes: Is my solution too bad? :frown:- Rhythmer
- Post #12
- Forum: Linear and Abstract Algebra
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Graduate A Question to Trouble Even the Best of You
Unfortunately, C++ is the only programming language I can use. Regarding adityab88's question, here is a solution I've just gotten: 1, 11, 31, 61, 101, 151, 211, 281 And it's the smallest possible because 361 is not a prime- Rhythmer
- Post #10
- Forum: Linear and Abstract Algebra
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Graduate A Question to Trouble Even the Best of You
What type of programming do we need to solve this sort of mathematical problems? C++ ?- Rhythmer
- Post #8
- Forum: Linear and Abstract Algebra