Recent content by RichardT

Ok so area G and H are equal to area of E and F because area of J = the area of K?

ok, one more thing, how do you assume that the area of H and G equal the area of F and E if only you know that they have the same height. You don't know the widths right? Because since i know that the width of H and G = 36 and the width of F and E equal 24, wouldn't the distances be different...

But when you go and solve it won't tension cancel, and initially since tension is the same for both objects wouldn't it be the same answer anyways? Oh and also i would have to divide by the total mass of both Jane and josh right? Or would i just use Jane because it only asks for her VERTICAL...

Ok so the total distance is 50 + 33.333+ 20 +20 +20 = 143.333km? I can understand that but I am given the possible answers and they are: 100, 133, 167, 200, and 267. Is there anything I am missing?

Would G be 30 as well and H 20? I am sorry that I am not really understanding this...

How did you find out that it was 40% of 50? I am not sure but basically the graph is saying that the man traveled more than 50km in the first 24 hours and than he traveled 20km?? How would i find out the area under that graph with no proper velocity?? And i have the velocity for area G and J i...

Ok, i can understand all the graph. However, how will that give me the total distance when i do not have all the times??

So, would the graph look like the picture i included? and Are my equations correct?

sooo.. not so sure about this but: d1 = v(T+24)? and d2 = 3/5v(T+48)? and honestly i have no idea for the 50km but is it d1 + 50km =T??

Ya that's what i believe the scenario is.

Oops sorry i meant ONLY 24 hours late... Sorry...

No its meant to be he arrived only 24 hours late rather than the 48 hours he would have been late So if he had 5 dogs for an additional 50km he would have been ONLY 50km late Hope that clears up some misinterpretations

Ok thanks!, but can you tell me why i cannot assume the last part as the dogs traveling 50km in 24 hours?

Its just that i have the possible answers and 73.333km isn't one of them, is there anywhere i could have gone wrong??

Ok, so that means i would have 3 equations: Equation 1. 50km/v + x/3/5v = 24hours Equation 2. d2 = 50km + x Equation 3. d2(with 3 dogs) = 3/5v x 48hours Correct? If correct, than: Equation 3: d2 = (144/5)v And plug that into Equation 2 which is d2=50km + x So sub in (144/5)v for d2 and solve...