Recent content by rifleman_d

Haha, yeah. It's a closed case for me, I'm pretty sure. Thank you both very much.

Okay, so \sqrt{(jωL+R)(jωC+G)} is our Propagation Coefficient. Our transfer function can be calculated as H(ω,l) = e-l*sqrt{(jωL+R)(jωC+G)} where l is the length. Gain was only defined as it's relationship to attenuation, which was given. The relationship is 20log(A) = -(attenuation)...

I apologize for the confusion but, the homework is actually written that way. It simply states that "Z_c = 52Ω in the LC Region" and that is it. This is my first course that uses transmission lines, and the professor seems to be trying to push half a semester's worth of material into 4 lectures...

Correct. The 52 ohms are also in the LC region which I forgot to mention before. So I have the equation: H(ω,l) = e^-l*sqrt((jωL+R)(jωC+G)) After plugging the numbers in, my professor suggested that I take the magnitude of the equation and plot it in MATLAB since the actual calculations...

I have used that equation before, but I am having problems connecting it with the attenuation. When I fill in the equation I have: 52 = \sqrt{(R+j(6.28×108)(8×107)/(j(6.28×108)(296×10-12)} Having all of that filled in, I could actually solve for R. But in this case, R would most definitely...

Homework Statement We are to assume an infinite transmission line with the following parameters: capacitance: 296 ρF/ft Zc=52Ω inductance: 8.0 × 10-7 H/ft We are told that a 100MHz signal is attenuated 31 dB per 100 feet and asked based on the information, assuming no leakage through...