Recent content by ringojuice

But really, thanks so much. What a lifesaver! I would have been stuck on this for a long time... this is what sleep loss does. I will probably be back on the forums often! Thanks again!

oh! I think we're onto my mistake here. I multiplied by .5 instead of by 2. what a silly mistake! I think if I solve this from here, I'll be fine. goodness! haha. thank you ever so much for your help! :) and I'm sorry I took your time with such a silly mistake!

right! I've gone through this step before, and I got 4.6981 for v. then I plugged that into the y displacement equation to solve for time and got an unsolvable quadratic: 4.905t^2 - 4.6981t +4.5 = 0

yes! I think we've got it this time. Thank you so much for spending this time!

let's see... there's no diagram that I know of.. I'm assuming the point from which it was thrown as "ground level" or zero vertical distance. I figure the height of the man throwing the pebble is irrelevant to its motion. That way, the pebble hits the window at 4.5 m from its starting point at...

I understand this explanation, but I fear I've miscommunicated the problem :( 4.5 meters is both the maximum height that the pebble reaches as well as the height at which it hits the window.

It is 5.0 m from the window horizontally, and 4.5 m away vertically.

sorry, I meant the maximum height that the pebble reaches relative to the point from which it was thrown..

no, I'm solving for the horizontal velocity of the pebble. I know the height of the trajectory, so the height from which it is thrown is irrelevant, I think. I am also given the horizontal distance to the window. Basically, my issue is that I can't figure out how to isolate and solve for any of...

no problem, thanks for your attention to this!

I also tried calculating the angle of the trajectory based on the distances given and came up with approximately 41 degrees... but from there I didn't know how to calculate the vector components of the velocity because no velocities are given.

The problem is really simple. It involves a guy throwing a pebble at a window such that when it hits the window at a height of 4.5 m, it has only horizontal velocity (it has reaches the top of its trajectory). The distance to the window horizontally is 5.0 m, and I am asked for the horizontal...

I have a similar issue.. I took AP Phys B last year and this year I can't remember the simplest things! I am completely stumped on a problem whose only known variables are the maximum height of the trajectory and the horizontal distance the object travels. I can't seem to figure out a way to...