Recent content by rizwanibn

Is there an 'i' with that?! Like A<T = AcosT + iAsinT And isn't this equal to Ae^(iT) ??!

@meBigGuy, Thanks..!:)

Hello... Can anyone tell me how sine and cosine came in ,above .(To the last of the attachment pic) Thank you.

Thanks very much. Got a very good understanding of it. So all the cubes has a pair of opposite sign and they cancel out each other.

Is it addition of subtraction in between...?

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I am not getting the answer to this question as shown in the textbook. Please help...! My attempt is in the last attachment. Thanks.!

Solved it again...! Thanks anyway... Looking at a concept that you understood couple of years ago and seeing it now wondering how did i...?! Whew...!

Hello. .Mr.Bruce.. Looking back at the same question,i find it difficult to remember how i solved it. Can you put some light on it. Magnitude of S=1...?! Thanks.

Well what i am trying to do is, Finding out the frequency of the continuous signal. Two times this frequency is the minimum sampling frequency,and inverse of that is the maximum time period. Please correct me if i am wrong. Thank you.

Ok i took the inverse Laplace transform. I got 20sin(1.3t) /2.7e^(t/2) Is the frequency of the wave (2pi f)=1.3 ? Or do i have to consider the exponential term as well?

< Mentor Note -- thread moved to HH from the technical engineering forums, so no HH Template is shown >[/color] Hi. Please see question no. 1 in the attachment. If i take the inverse Laplace transform or the Z transform, how can i actually get the value of sampling period 'T'. or is there any...

Maybe I'll get in touch when i find out.

Thank you for your concern.