Recent content by rjunior
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FFT for Sinusoidal Signal: 100 kHz, Peaks @ k=100, 412
Dear uart, Thank you for your attention. I have developed the equation but how i do to get signal frequency. Thanks in advance df = fs/N f1 = 100 df fs - f1 = 412 df fs - 100 df = 412 df fs/N (N - 100 ) = 412 fs/N N - 100 = 412 N = 512- rjunior
- Post #5
- Forum: Engineering and Comp Sci Homework Help
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FFT for Sinusoidal Signal: 100 kHz, Peaks @ k=100, 412
uart, Thanks for your attention. Let suppose it is X(0).- rjunior
- Post #3
- Forum: Engineering and Comp Sci Homework Help
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Smoothing Data with Average Calculation
How to make it causal: y (n) = x ((n-1) + x(n) + x(n+1))/3- rjunior
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- Average Calculation Data
- Replies: 3
- Forum: Engineering and Comp Sci Homework Help
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FFT for Sinusoidal Signal: 100 kHz, Peaks @ k=100, 412
Suppose you have the FFT of a sinusoidal signal sampled at 100 kHz and it has energy peaks at k = 100 and k = 412. How many points is the FFT? What is the frequency of the signal?- rjunior
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- Exercise Fft
- Replies: 6
- Forum: Engineering and Comp Sci Homework Help