Sure I can calculate the value of t2 in this scenario, however my next task is to rewrite this equation as a generic formula to find t1, using the same technique you have shown me. Therefore, sure I can look at t2 in both cases but how will I know which one is correct. If I provide accel, decel...
Rounding
v = 24.59m/s OR v = 0.41m/s
I mean looking at it, I know which is more likely, is there a way to confirm which of these two values is correct?
Finally...
Solution A:
t1 = 24.593386622
v = v0 + at
v = 1 * 24.593386622
v = 24.593386622m/s
Solution B:
t1 = 0.406613378
v = v0 + at
v = 1 * 0.406613378
v = 0.406613378m/s
I found it easier to do the steps logically:
t1*25 - 2t12
And then work out the steps one by one...
Sorry, I read it over and I realize how dumb I sounded! I used this only a few steps ago!
So I have:
t3 = (at1)/2
t3 = (2*t1)/2
t3 = t1
t1 + t2 + t3 = 25
t1 + t2 + t1 = 25
(2t1) + t2 = 25
(t12) + (t1t2) = 10
Apologies, I typed it incorrectly.
(1/2*t12) + (1*t1*t2) + ((12t12)/4) = 10
(1/2*t12) + (t1t2) + ((2t12)/4) = 10
(1/2*t12) + (t1t2) + ((t12)/2) = 10
(t12) + (t1t2) = 10
I still have 2 unknowns, but I also know t1 + t2 + t3 = 25. I have got to a stand still again!
I see..
Oh I see, sorry i was confused as v was the constant velocity during t2, and I was substituting in the velocity as a result of acceleration, but you made me realize that this velocity is the final velocity of the acceleration period :smile:
v=v0+at1
v=at1
So inserting this into...
Im really stuck...
I can't seem to figure out how v=v0+at for the acceleration deceleration period will help me find v? Am i being stupid? I have been looking at this for hours and can't seem to slot the final pieces together.
t1+ t2 + t3 = 25
(½*t12) + (vt2) + (t32) = 10
How does using...