Recent content by rocapp

Thanks a bunch! That's what I needed.

Thanks! I think I understand, but what about the t=0 in R? Does this value not count since there is already an incompatible value in its components?

Homework Statement Which of these three points falls on the line? l: r(t)=(i+2j)+t(6i+j-5k) P(1,2,0); Q(-5,1,5); R(-4,2,5) I have the answer, but I don't understand why P and Q fall on the line but R does not. Is it because the i and j magnitudes are different for R?Homework EquationsThe...

Ok, I tried this: B=mu*I/2R B1=4PIx10^-7 * +1 / 2*(1.1x10^-2)= 0.000785 T B2=4PIx10^-7 * -1 / 2*(1.1x10^-2)= -0.000785 T I=V/R V=PHI1-PHI2/t PHI1=A*B1 PHI1=PI*(8x10^-4)^2 * 0.000785 =1.58x10^-9 PHI2=A*B2=PI*(8x10^-4)^2 * - 0.000785=-1.58x10^-9 V=(1.58x10^-9)*2/(8x10^-2) V=3.95x10^-8...

Homework Statement A small, 1.60-mm-diameter circular loop with R = 1.10×10−2Ω is at the center of a large 120-mm-diameter circular loop. Both loops lie in the same plane. The current in the outer loop changes from + 1A to -1A in 8.00×10^−2s . What is the induced current in the inner loop...

Doh! Thanks a bunch!

Thanks! But for the second part, I'm not sure of what to do. F=qvB 1.3=q(3.46)B But where does q come from?

Homework Statement A 7.00-cm-long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wire and rail is 0.320Ω . Pulling the wire with a force of 1.30N causes 4.50W of power to be dissipated in the circuit. What is the speed of the...

Homework Statement A capacitor is discharged through an 80.0 ohm resistor. The discharge current decreases to 23.0% of its initial value in 1.50ms . What is the value of the capacitor? Homework Equations t=RC The Attempt at a Solution 1500 μs = 0.23 RC RC= 6521.74 C=...

Anyone know why?

That wasn't correct. The correct answer was: 9.2×10^4 s^-1

So then: ((3x10^18)/(4*PI*1.0x10^8)) * (PI*3.5x10^-6) = 26250 Photons/s Correct?

Not sure of this either, but here is my thinking: Number of Photons/s = (Source Photons/s)/(Surface Area of sphere formed by the distance) * (Surface Area of eye) Photons/s = (3x10^18 photons/s)/(4*PI*1.0x10^8 m^2) * (4*PI*7x10^-6 m^2) Photons/s = 2.1x10^5

Homework Statement A typical incandescent light bulb emits ~3x10^18 visible-light photons per second. Your eye, when it is fully dark adapted, can barely see the light from an incandescent light bulb 10 km away. How many photons per second are incident at the image point on your retina...

Thanks!