Find the velocity and strength of magnetic field from the given info

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Homework Help Overview

The problem involves a wire being pulled along a conducting rail within a magnetic field, focusing on determining the speed of the wire and the strength of the magnetic field based on given parameters such as resistance, power, and force.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between power, force, and velocity, with one participant calculating current using the power and resistance values. Questions arise regarding the relevance of certain equations and the need for charge in the context of the magnetic force equation.

Discussion Status

Participants are exploring different equations and their relevance to the problem. Some have provided calculations, while others are questioning the applicability of specific formulas. There is a recognition of the need to clarify the role of charge in the context of the magnetic force equation.

Contextual Notes

Participants are navigating the constraints of the problem, including the need for additional information regarding charge and the implications of the equations used. The discussion reflects uncertainty about the connections between the various physical quantities involved.

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Homework Statement



A 7.00-cm-long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wire and rail is 0.320Ω . Pulling the wire with a force of 1.30N causes 4.50W of power to be dissipated in the circuit.

What is the speed of the wire when pulled with 1.30N ?

What is the strength of the magnetic field?

Homework Equations



ε=vBL
P=Fv
I=ε/R

I=sqrt(P/R)

The Attempt at a Solution



I=sqrt(P/R)

I=sqrt(4.5/0.32)=3.75 amps

I=ε/R

3.75 amps = ε/0.32

ε=1.2 V

ε=vBL

(1.2 V)=v(?)(0.07 m)

I'm not sure how to find the magnetic field, which I obviously need for both parts. Please help! Thanks!
 
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You wrote P = Fv as a relevant equation. Maybe it really is relevant. :wink:
 
Thanks!

But for the second part, I'm not sure of what to do.

F=qvB
1.3=q(3.46)B
But where does q come from?
 
The equation F = qvB is not relevant here. Now that you have a value for v, why not go back to your earlier equation ε = vBL?
 
Doh! Thanks a bunch!
 

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