Okay, so basically I used the non-calculus method to find the time it takes for the ferris wheel to travel that arclength (312.32seconds), given the right triangles I created. I am on the second part of the question where I have to relate the rate of change of the angle inside my ferris wheel to...
Okay, so what I have so far is this: I'm going to make the circle (ferris wheel) centered at the point (0,33). Therefore, my equation of my circle in terms of x and y is as follows:
x^2+(y-33)^2=900
It can also be rewritten as +/-sqrt(900-x^2)+33
Now that I have my circle, I know my line(s)...
So representing my straight line I have y=mx+b, where m is my slope. I'm assuming the equation of the circle that you're referring to is the circumference? (2pi*r). In that case, in order to find where they intersect, I set them equal to each other?
Okay, I understand part of which you are saying, but I'm not sure which equations I should be using to find those two points? I know the two tangent lines are going to have different slopes (because the camera is mounted at a height of only 15metres, but midpoint of ferris wheel height is...
Urgent First-Year Calculus Word Problem! Help needed ASAP!
Homework Statement
Hey this is a first year calculus word problem:
A third design question involves our plan to provide interested tourists with a video of themselves on our biggest Ferris wheel. The idea is to place a camera on...