Recent content by rodjav305

So all i would need to do it add up the masses of the boy and the chair which is 42.55102 kg and multiply by acceleration which should give me the result 10.0 N

Ok so m would be the mass of the boy, chair and spring(addition of all of the masses)? Or just adding the mass of the boy and subtracting the tension and chair mass. For acceleration i would use the result i got from a and plug it in. If i add up all the masses: 36.020408 + 6.530612 +...

So that result is wrong. Another idea that i have is take all the forces and subtract it and get that as a mass and multiply with acceleration... 36.020408-21.785714-6.530612 = (7.704082)(0.235012)= 1.810552 N I don't know if that wrong, it looks wrong to me because of the little force...

Ok so i drew a FBD, i got the force of the boy minus the force of the chair (36.020408 -6.530612) = 29.489796 N exerted on the chair...Is that right?

Homework Statement Homework Equations a=F/mThe Attempt at a Solution For part 1 I did this : Mass of boy: 353 N/9.8m/s^2 = 36.020408 kg Mass of chair: 64 N/9.8m/s^2 = 6.530612 kg Then : (36.020408 + 6.530612)a = 2(213.5)-353-64= 10N a= 10 N/ (36.020408 + 6.530612) = 0.235012 m/s^2 I...

hmmmm this is what i just did for x2 x2= (-42m) + (-4m/s)(6.0s)+ 1/2(-4.0m/s^2)(6.0s)^2 = -66m + (-72m) = -138m It still gives me a wrong answer...can you explain where i went wrong?

How would I go upon doing that? A couple of people told me to use two equations

Homework Statement I have put the diagram in an attachment. I need to find position at 8 seconds.Homework Equations X = ½ at² + vt + x The Attempt at a Solution -34m + (-3m/s)(8.0s)+ ½ (-4.0m/s2)(1.0s)2 = -165 meters

Sorry about that, but no worries as I managed to do the problems myself.

Ok so for the first part my questions I do not understand how to start it off. 1. Calculate the concentration in molarity. 4.500 grams of CuSO4.2H2O is dissolved in water to make 250.0 mL solution. The concentration is labeled as M1. 2. A student used 10.0 ml of M1...