Recent content by roe

Aha! So, if I say: h(x) = sqrt(t-3) = (t-3)^.5 f(t) = t^.5 g(t) = t-3 f'(t) = .5(t)^-.5 g'(t) = 1 so: h'(t) = f'(g(t)) * g'(t) --------> h'(t) = f'(t-3) * 1 --------> h'(t) = 1/2 * (t-3)^(-1/2) ----> h'(t) = 1/2 * 1 / sqrt(t-3) -------> h'(t) = 1 / 2 * sqrt(t-3)...

I'm thoroughly confused as to how and work this problem. I thought I had an ok understanding of the chain rule when I started the section's homework, but this question has me ready to gorge out my eyeballs! The Problem: --------------- Find:dy/dx at x = 2 Given: y = (s+3)^2, s = sqrt(t-3)...

OK, I'm not seeing how to determine when it hits the ground. I've been doing 1-dimensional problems for the last couple of hours but I'm really not understanding how to set this problem up. What I have so far is: Vxi = (100 m/s) cos 55 degrees = 57.36 m/s Vyi = (100 m/s) sin 55 degrees =...

<b>Q:</b>A projectile is shot from the edge of a vertical cliff 60.0 m above the ocean. It has a speed of 100 m/s and is fired at an angle of 35.0 degrees below the horizon. How far from the foot of the vertical cliff does the projectile hit the water? My take on the problem...