Recent content by romolo

Right. And remember that, for the original problem, zero is part of the solution. So your interval should start with a [ instead of a (

Your first answer is closer than your second answer. If you're restricted to [0, 2pi) then there's no need to mess with the k values. Two hints: cos(0) = 1 and cos(pi) = -1

Hi John, I'm new here, too. I like the idea of using an application to prove a pure math theorem, but I don't think I have a very good visual of your explanation. Can you post a diagram so I can see what's going on?

I was wondering if anyone could help me out about trig identities. I'm a HS trig teacher and I'm going "by the books" and instructing them to manipulate the left and right sides of the identity independently of each other. They are not to treat it like an equation, e.g. no moving terms from...

Your answer doesn't look right to me. Why not try a graphical approach? From 0 to 2pi there will be 4 periods, and it looks like there will be 4 intervals in your solution. Oops! The period is 2pi, not pi/2. Yes, it seems your solution is right. Without a graph, I like your approach of...

Careful of dividing by x! It's OK in this problem since x=0 is an extraneous solution, but you do run the risk of losing a solution.

I think the following question would work too. It is simpler... "Which way is your tribe?" Either way, the man points to the Cuddly-Wuddly tribe, yes?