Recent content by rovert

I now see what you are saying. See how bad I am at this stuff. I didn't really even know what you meant at first with the spherical coordinates. By using this r^2 sin(other stuff), I will be able to eliminate the 1/(r^2) term in my integral, correct? Is the other stuff in the volume element...

OdlerDan, it actually makes it worse for me to do it in spherical coordinates. The major problem here is I am not up to parr on the math it takes to do quantum mechanics (I have a mainly chemistry background). I have pulled all the constants out and am now left with: ∫ e^(-Zr/a0) (1/r2)...

OK, now I have: ∫ π^(1/2)(Z/a0)^(3/2)e^(-Zr/a0) (b/r2) π^(1/2)(Z/a0)^(3/2)e^(-Zr/a0) dr which is equal to: b∫ π^(1/2)(Z/a0)^(3/2)e^(-Zr/a0) (1/r2) π^(1/2)(Z/a0)^(3/2)e^(-Zr/a0) dr Now I am stuck again because I need help with this integral. Anyone? Thanks

Homework Statement Consider a perturbed hydrogen atom whose Hamiltonian, in atomic units, is: H= -1/2(∆^2) – ½ + b/(r^2) (∆ should be upside down), where b is a positive constant. The Schrodinger equ. for this hamiltonian can be solved exactly for the energy eigenvalues. The...

Thanks for your help. I think I've got it now. Since I can make the Born-Oppenheimer approximation, I can leave KE for the nucleus out (basically ignore the nucleus all together) which I know is a HUGE assumption to make, but that is what the problem instructs.

Be has 4 electrons. Yes, they are assumed point charges. Electron spin should be included. Does it start with H=(-ћ2/2m)∑…? That is where I thought I should start, but am stuck after that. I have never seen a Hamiltonian developed for a many-electron atom.

I have a problem that uses the QM Hamiltonian for the berylium atom, but I am having trouble finding this Hamiltonian using the Born-Oppenheimer approximation (leaving out the nuclear-nucler and nucler-electron terms). Any know how to get this?