Thank you for the welcome and the reply!
You know, I had thought about doing that after I posted, but wasn't sure if that was the right way to approach it.
So, if I switch them, I get the standard form as:
dx/dy + [4/(y+1)] * x = y / (y+1)
So my integrating factor is:
e^∫P(y) dy ; P(y) = 4 /...