Recent content by ruck101

Reply Anyone...?

I get the same exact thing.

reply dang, I did that the first time I tried this..lol. ok let me reattempt this.

Reply thanks for the reply. ok, I converted 3.45 cm to m = .0345 m then, I got the linear velocity = 11.4 x .0345 = .3933 m/s next, I got the linear acceleration = -.96 x .0345 = -.03312 m/s^2 ok, I plug all of this into a kinematics equation and get 5.94 m, does this sound right? Thanks!

Here's the problem: diameter = 3.45 cm angular speed = 11.4 rad/s angular deceleration = -.96 rad/s How far does the coin roll before coming to a stop? How would I set this problem up? Thanks!

Problem How would you find this same type of problem, but in addition, there's a constant air resistance force? Thanks.

Banked Curve Hehe, guess I should have done that in the first part. Anyway, I drew a freebody diagram and got the Normal Force = 11119 N, and the Friction force = Normal x Coefficient = 5448 N. Is that the only centripetal force or is there also the sin component of the weight? I've added sin...

Hey all! Brand new to PF. Anyway, I'm having trouble with a problem involving centripetal force. Here are the givens: Friction coefficient = .49 Angle = 19 degrees Radius = 46m mass= 1200 kg Question - How fast can the car take the curve without skidding to the outside? Thanks ahead of...