I'm having a nightmare with this question aren't I?!
We are advised that Q=(ω/Δω)
or Q=(f/Δf)
Can I work out Q using either of these equations from the information shown in the graph?
I'm so confused..
Sorry BvU, I've got myself a little confused! You are correct with regards to the values of the plots.
Plot a is 10 and plot b is 7.
It seems I'm a bit of a numpty today!
Ah, silly me! I see my error now.
Yes they are from picture 790685 post #5
Q can be calculated from ω/Δω
where ω is the value at the peak of the curve
and Δω is the width of its peak at the halfway point
The graph is difficult to read but for plot b i originally took that to be 50/(55-45)...
Ok, here is my attempt.
I've taken Q to be 7 for plot a and 10 for plot b.
Rearranging Q=2π (E/ΔE)
ΔE/E = 2π/Q
For plot a:
After one cycle 2π/Q = 0.1
After two cycles (0.9*0.9) = 0.01
After three cycles = (0.81*0.9) = 0.001For plot b:
After one cycle 2π/Q = 0.37
After two cycles =...
The question states:
Using equation Q=2π (E/ΔE) calculate how much original energy each of the oscillators will have left after three cycles.
Where ΔE/E is the fractional energy loss per cycle of the oscillation.
As the question asks how much original energy would be left after 3 cycles, I...
Thanks
Indeed, it was what I was asking. With reference to the earlier post, it turns out the graph was difficult to read and I was advised to read it so that it fitted the equation.
Thanks for your reply though, appreciated,
Homework Statement
The rate at which the mass–spring system loses energy to its surroundings is referred
to as the Q-value for the oscillator. The Q-value is defined as:
Q=2π(E/ΔE)
I need to find ΔE/E, which is the fractional energy loss per cycle of the oscillation.
How would I rearrange...
1. Taking measurements from Figure 1, determine the value of Q for each of the oscillators represented. Explain how you obtained your answer.
Where Q= ω/Δω
2. Using equation 5.19 which is the rate at which the mass–spring system loses energy to its surroundings is referred
to as the Q-value...