Recent content by ryan750

it sounds like u think uve got sumthing to blow the minds of the scientific community with. I guess i believe the same with my theories and mine predict that information isn't lost. It is awfully simple but wil keep tight lipped till more thinking has been dun

my astronomy teacher said that black holes have zero volume and infinite density. Also he said they all have fixed mass. i really don't get the first two and personally don't think this is true.

show that INT x sec^2x dx = pi/4 - ln2/2 (between pi/4 and 0) pls help i don't know where to start i know it is integration by parts - just don't know how i should rearrange it. thanks

Xn+1 = Xn(2 - NXn) => (Xn+1)/Xn = 2 - NXn => NXn = 2 - (Xn+1)/Xn => NXn = (2Xn -Xn+1)/Xn => N = (2Xn - Xn+1)/(Xn)^2 => N ~= Xn/(Xn)^2 => N ~= 1/Xn Which is a good estimate for the recipricol. I found sum1 that could do it. i didn't think about just rearranging the formula.

it works for all values of N and u can use any value of Xn - but u would preferably choose a number that is royughly 1/n. So if N was 7 u would use 0.1. If n was 53 u would use 0.02.

can any1 explain why this iteration: Xn+1 = Xn(2 - NXn) can be used to find the reciprocal of N. I don't ned proof or to show that it does but i would like to know if sum1 can break it down and explain how it does it.

so the light provides the energy to valence electrons in the n type to be excited and they are attracted to the p type and combine with holes. This process carried out produces energy changes to the electrons and holes which creates the potential difference seen. is this right?

sorry - so electrons from type move top n tyoe and holes move from n tyoe to p type. can i just ask what holes are? i know they are positive but that's it.

ok - i just need yto clear this subject up once and for all - the l.e.d has no power supply - just a voltmeter to take readings with. so if there was no power supply why would the electrons move from the p - type material to the n - type material when this type is more negative right. As...

okay so no relaxation either - man - all of my course terminology has gone so out of the window - but I am glad that I am going to get it right. and thankyou for welcoming me - i can't wait to get stuck into all of these rooms and all of the interesting topics out there.

also last thing - the potential difference occurs in the l.e.d because of the energy changes to the electrons. The electrons move from higher to lower and from lower to higher levels - so these energy changes are the potential difference in the l.e.d. i know that's basic stuff but i just want...

oh yes and jus to clear up - when the valence electron moves thru the conduction band to fill the positive holes in the valence band of the p - type semiconductor - the excited electron relaxes and emits light yes.

right i really think I've got it now - thanks for persevering with me - i probably would have lostthe marks in the exam if i had said it was due to the photoelectric effect - I am so glad i have researched it now. oh and sorry for doubting u guys - i had no idea that u were expert in the subject...

its ok i have just emailed a source that is expert on the subject - it is a diode company and they should be able to explain all - thanks for all ur help

ok - u seemed pretty clued up about this subject: please could u give a concise account to this question - it would be greatly appreciated - even if it means repeating some of the details that have been said on this thread already - pls: Light from a filament lamp is incident on a l.e.d that...