Oh so from there it is just simple differentiation, I finally see. I think you mean (d^2x)/(dy^2) = (-2/9)x^(-5/3). Thank you very much AmaniKaleo and everyone else, I really appreciate the help and patience.
Yes I understand that completely but for that and my equation I wouldn't know how to use implicit differentiation to find y'' and y''. Sorry if I seem stupid.
Thanks for that, I understand what you did but a stupid question, is that implicit differentiation? And I'm still unsure about finding y'' and y'''. Thanks again.
But as dy/dx=1/(3y^2) doesn't that equal (1/3)y^(-2). Now finding (dy^2)/(dx^2) is confusing. I'm sorry if I seem slow but I just have never done implicit differentiation and I'm about unsure what to do.
Thanks AmaniKaleo but that's the method I will be using to verify my answer. As the question unfortunately states I need to use implicit differentiation and that's where my worries lie.
Yeah sorry guys maybe i should state the whole question. Here it is:
Use implicit differentiation to produce a degree 3 polynomial approximating the solution of the Initial Value Problem (IVP):
(dy/dx) = 1/(3y^2); y(0)=1.I know to get the degree 3 polynomial approx. I will have to use the...
Homework Statement
Hi everyone, name is Ryan. This is my first post here, seems like a very beneficial forum. I look forward to being helped and helping others. Anyway I'm trying to teach myself Implicit Differentiation but there doesn't seem like much useful resources online and I don't quite...