Recent content by ryanx806

Okay! Thank you so much! I think that's what I was originally trying to do, but my professor's example made me question it. I really appreciate your help though!

So... (90kg)(7.6m/s) + (120kg)(4m/s) = 1164kg*m/s Does that mean that the final velocity = 1164/(90kg + 120kg) ? And if so, how do I know which direction they are going after the collision?

My professor gave us an example that uses the equation for conservation of momentum (mvi=mvf), which I understand. But I'm confused on whether I need to solve this equation for both players in both axes (which would give me 2 final x-velocities and 2 final y-velocities) or if I just use the...

Homework Statement A halfback with a mass m1=90kg is running up field with a speed of v1=7.6m/s. He is tackled by an opponent with a mass of m2=120kg, who approaches the halfback at an angle of 30 degrees with a velocity of v2=4.0m/s. Assume the collision is perfectly inelastic. a)...