Recent content by sakin

I appreciate the help, really I do. I'm just trying to get into a sonography program, take two classes this summer, get ready for fall term and still raise two daughters and try to be a good wife. I realize I'm paying now for majoring in registration with a minor in drops back in the day but...

Problem is, the teacher has even LESS patience than what I have seen in darker moments here. He's ram-rodding through an 11-week summer course and really has no patience for any of us trying to get him to explain problems based on concepts he feels he already covered. So again, that's why I'm...

see where one could find this both arbitrary AND contradictory? I combined like terms at [x^2-2x+1-1], where 1-1 removes that term, and now I find that I wasn't supposed to follow that rule in this case? Again, you may find this as elemental as tying your shoes but I obviously don't. I find...

see my above posting. This may make perfect sense to you but I'm still trying to follow your formula and getting nowhere. 2[(x-1)^2-1]+7 becomes 2[x^2-2x+1-1]+7 which I see as 2(x^2-2x)+7 so what happened? where did a -2 outside of the parenthesis come from? Can you explain to a...

mistyped a character- my mistake. so can someone explain, in layman's terms, how one concludes that 2(x-1)^2+5 is the solution? here is my beef- your process does not jibe with the the way the examples are worked in the book. I don't see the 7 being moved over to the other side in the...

folks, this is a COLLEGE ALGEBRA course... not calculus. The question asked to put the equation in vertex form by completing the square. f(x)=2X^2-4X+7 now I set f(x) to y. I know you purists out there probably hate to see this but bear with me, I'm not, repeat NOT a math aficionado. I...

with all due respect, partner, you're spinning your wheels in gravel. the problem was to put the quadratic into vertex form by completing the square, vertex form being y= a(x-h)^2+k and I did that via f(x)=2(x-2)^2+3

y-7=2x^2-4x; y-7+4=2x^2-4x+4; y-3=2x^2-4x+4; y=2(x-2)^2 +3 just as I had done it in my first attempt, original posting.

well the question asked for vertex form, and it turns out I had vertex form... it's just with an 11-week course it's all too easy to forget a bunch of stuff. y=2(x-2)^2+3... looks like a vertex to me. how many points do I get for fixing my own problem? :smile:

Homework Statement find the vertex by completing the square: f(x)=2x^2-4x+7 Homework Equations The Attempt at a Solution numerous attempts yet not one looks right. one was as such: y-7=2x^2-4x; y-7+4=2x^2-4x+4; y-3=2x^2-4x+4; y=2(x-2)^2 +3... I could see this as...

OK thanks to all... I graphed the beast with x=12.5 and Rmax=312.5. Prof is a sadist, that much I know.

the moment of truth...? soooo... if I were to graph this beast, I would be looking at a negative quadratic function whose vertex would be some value of x, and y=312.5? Sounds like a major SWAG of a graph, to be sure...

OK, how about the NON-math/accounting/physics major's interpretation of the above?:redface: I'm looking at this and really am not sure of where to complete the square. Would I be halving 50 and then squaring the result, or does another value represent b? A fresh morning look at the problem...

Homework Statement Graph: R(x)=x(50-2x). Determine the maximum value of R. Homework Equations this particular question doesn't lend itself to a relevant example in the Rockswold text. The Attempt at a Solution at first, I tried graphing it on the TI as -2x^2+50x but it is a...