Recent content by salomi

Can't thank you both enough! Simple problem but man was it giving me a heck of a time :) Have a great new year fellas!

my original power was 1W. my new power is 4W since my voltage was doubled. I really appreciate Doc Al and technician for the past hour! Great forum you guys!

Again thank you very much for all your help. I finally understand what you both are telling me. If the voltage across a resistor is doubled, the power dissipation in the resistance increases by a factor of 4. But when i use 2V^2 i get 4V. So now i divide by resistance? Given the information you...

I think this is where i am most confused. What is my Voltage for the problem? It can't be the power dissipated, right? Trying it your way, if i double the V, my power will also double? I feel like I am not given enough information and i would have to calculate my current in order to get the...

Thank you so much for the quick responses. Although the answer is probably right in front of my face, i am still getting confused by the fact that my power dissipated is in watts. If i plug in the numbers, my equation reads " 1W^2 divided by 10 ohms which gives me 0.1 Volts? But the question is...

hi just needed to know if the power dissipated by a resistor is equal to the total voltage. I am having a hard time understanding a problem i was given, and i know the formulas to find power dissipated, but i can't use P = I squared * R or P = V squared / R for this question... " A 10 ohm...