1. Is this right:
Mol of AlCl3 = 0.112mol
Mol of NaOH = 0.125mol
mass = (0.112mol)(78.03g/mol)
= 8.74g
b)do I multiply 0.125 mol by the mols of 3NaCl. Then subtract 8.74 from the anwser?
1. Aluminum chloride (15.0g) + sodium hydroxide (15g) = double displacement reaction.Predict mass of aluminum hydroxide produced. What mass of the excess reagent remains unreacted?
2. What mass of copper(II) sulfate pentahydrate is needed to prepare 150.0 mL of a 0.125mol/L solution...