Recent content by SamLing2000

Any help is appreicated.

Homework Statement A 330 kg roller coaster car sits on a horizontal track. Ahead of it is a vertical loop with radius of 6.85 m. The car is given an initial speed of 23.4 m/s and the car successfully traverses the loop. What is the maximum amount of energy taken away from the car by friction...

So I tried again using the a from that equation and I was still unfruitful. What I did was found a = ug vf = √(vi^2-2aΔx) i used the minus because when i used the plus the velocity actually went up, and i assumed because it was the deceleration caused by the friction it should be a negative...

Thanks for the response, but I am a bit confused as to what to do, and what you said. First of all I'm curious as to why the RHS is the energy LOSt to friction. Secondly, to find the acceleration I assume i must make 1.18(a)*.42 = uk(N) which is 1.18a(0.42)= 0.367(1.18)(9.8) is that correct...

That is what I did. If you follow my work. Is the procedures right? I did i simply do my math wrong?

Homework Statement A 1.18 kg block slides across a horizontal surface directly toward a massless spring with spring constant 5,803 N/m. The surface is frictionless except for a rough patch of length 0.42 m that has coefficient of kinetic friction 0.367. The initial velocity of the block is...