Recent content by SampleLow
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Stopping a rod moving with constant omega
It is possible the question is flawed. The other end. Would the normal reactions on either side not change suddenly? I was assuming constant power. But why will it only slow down? My doubt exactly. What is this? Could you give me an example of such a problem? Maybe just link it.- SampleLow
- Post #13
- Forum: Introductory Physics Homework Help
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Stopping a rod moving with constant omega
I don't really understand.- SampleLow
- Post #9
- Forum: Introductory Physics Homework Help
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Stopping a rod moving with constant omega
Ok. So when I add a force F, the friction becomes μ(mg+F).- SampleLow
- Post #7
- Forum: Introductory Physics Homework Help
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Stopping a rod moving with constant omega
Then what is it about?- SampleLow
- Post #5
- Forum: Introductory Physics Homework Help
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Stopping a rod moving with constant omega
What do you mean? If it is applied at one point, then that element will have a bending moment. What is incorrect?- SampleLow
- Post #3
- Forum: Introductory Physics Homework Help
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Stopping a rod moving with constant omega
Friction before force is applied, f=μmg. After force is applied on element dx, at a distance x from hinge, the is a bending moment on that element dM which is given by normals on either side (say N1, N2) by dM=N1-N2 and N1+N2=mg+F.- SampleLow
- Thread
- Friction Mechanic Omega Rotation
- Replies: 13
- Forum: Introductory Physics Homework Help