Recent content by SamQP

  1. S

    Pressure due to a perpendicular wind

    I have the same questions as Liam right now. Both trying to figure them out together over the phone :P
  2. S

    Pressure due to a perpendicular wind

    Ah sorry, the question states 'a brick wall rests on flat ground' so I think we are supposed to assume that it has no foundations :)
  3. S

    Simple harmonic motion of a charged particle in a rod

    Just substitute in :) Use ω=2∏/T and rearrange.
  4. S

    Simple harmonic motion of a charged particle in a rod

    So I come out with the net force F=-(2kqQx)/R3 This agrees with Simple Harmonic Motion as the net force (the restoring force) is directed towards the equilibrium position. Am I right in saying that it also agrees with SHM as when used with F=ma, acceleration is at a maximum when x is also at a...
  5. S

    Simple harmonic motion of a charged particle in a rod

    So the expansion for F1 would leave me with (kQq/R)+(kQqx)/2R, and for F2 would be the same but with a minus sign in the middle. What the would I do with this. When I combine them I would be left with Fresultant=(kQqx)/R Is this correct? How would I relate this to simple harmonic motion?
  6. S

    The original mass of a gas in a leaky cylinder

    Homework Statement A leaky cylinder, at 0oC contains gas with a pressure of 18.0 atmospheres. After being kept at 20oC for 24 hours, the pressure is now 16.3 atmospheres and the masss has fallen by 1.2kg. What was the gas' original mass? Homework Equations The Attempt at a...
  7. S

    Simple harmonic motion of a charged particle in a rod

    So, at any given point the force on charge q would be F1-F2 where F1 is the force from the closest end = (kQq)/(R-x) and F2 is the force from the closest end = (kQq)/(R+x) Would I then combine these to get Fresultant=(2kQqx)/(R2-x2) or am I going about this all wrong? Where (and how) would...
  8. S

    Simple harmonic motion of a charged particle in a rod

    Homework Statement Two points, each of charge Q, are fixed at either end of a frictionless rod of length 2R. Another point charge, of charge q (not Q) is free to move along the rod. Show that if charge q is displaced a small distance x (0<x<<R) from the centre of the rod, it will undergo...
Back
Top