Recent content by samuelphysics

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    How to know which gauge transformation we should use?

    good luck with your phd! don't worry about that last question, it was a result of curiosity when you shared that paper.. i have also to wory about m courses instead of drifting away. thanks for your discussion, @haushofer
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    How to know which gauge transformation we should use?

    Oh i see thanks for your efforts in explaining these, please if i could ask one more thing: when you replied by this Could we know how this ##\epsilon=1+\beta e^2## represents the Killing spinor for the IWP metric which has a time-like Killing vector while the other two orbits correspond to...
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    How to know which gauge transformation we should use?

    Oh ok, concerning what you said here I was asking because if you go back to the paper you cited, specifically, you can see that the authors (upon the use of gauge transformation) turned the original very general ##\epsilon =\lambda 1 +{\mu}^{i}e^i+\sigma e^{12}## to 3 canonical forms which are...
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    How to know which gauge transformation we should use?

    Thanks for your answers guys! @haushofer sure your answers always do help, I just want to make sure of some stuff going on in my head as I am trying to solve KSE's for the first time. So why do people have the right to simplify a spinor that way? Then in the paper you cited, you're saying...
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    How to know which gauge transformation we should use?

    Spinors in $N=2, D=4$ supergravity can be simplified using gauge transformation and thus canonical spinors can be found. In the case of $N=2, D=4$ supergravity the gauge transformation Spin (3,1) is used. My question is how do we know which transformation can be used in a certain theory in order...
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    What does ##\delta F=0## mean?

    This sounds more like "fermion" is still transformed into the "boson" so is it that spin connection is a boson? or else what is the point of mentioning this? Do you mean that the metric is a boson? happy 2016 @haushofer
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    What does ##\delta F=0## mean?

    even though ##\delta F=0##? Doesn't this quote contradict with the ##\delta F=0##?
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    What does ##\delta F=0## mean?

    @haushofer thanks very much for your answers. I really like the fact that you put an analogy but I did not get the whole picture of the analogy and how it plays a role in answering my first question which says: "Does it imply that for a background to be supersymmetric, then fermions must not...
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    What does ##\delta F=0## mean?

    Links for [1] and [2] are below. Please have a look here section 12.6 [1]. It says here that Given the action of a supergravity theory, it is generally useful to search for solutions of the classical equations of motion. It is most useful to obtain solutions that can be interpreted as...
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    Why do those two terms add here?

    ummm, thanks a lot @Emilie.Jung and @nrqed ! So, you mean this is not a property of a Hermitian metric but is an additional condition on that Hermitian metric? Because EmilieJung said it was a property. If EmilieJung is right then doesn't this property have a proof? That was mainly my question.
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    Why do those two terms add here?

    The past post got a little messy, what I meant to ask you was when you said So why is it that hermiticity makes those two terms vanish? Excuse me for double posting
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    Why do those two terms add here?

    @nrqed But why do the dz^i terms commute?
  13. S

    Why Complex Scalars in 4D Supersymmetric Theories?

    Maybe @fzero can give us an insight on how to tackle this and if there a different approach to the answer?
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    Why Complex Scalars in 4D Supersymmetric Theories?

    @haushofer But you start by setting as a given that the lagrangian holds scalar fields or complex fields and you build on that, meanwhile the question was why is this the case? Why in 4D you have complex scalars and in 5D you have real scalars? It seems you answered the question by setting the...
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