Recent content by sara167

Thank you so much for all your help

Hoop= v^2/g hollow sphere= 5/6v^2/g solid sphere= 7/10v^2/g If I switch them to a common denominator then the order from greatest to smallest height would be: Hoop Hollow Sphere Disk and Cylinder Solid Sphere Correct?

3/4 v^2

1/8(v^2+v^2)/g = 1/16v^2/g?

I think I get it. So for a solid disk or cylinder: h=2v^2/2g This shows the same height as the hoop correct? The height for the hollow sphere would be 4/3? The height for the solid sphere would be 4/5?

So from the first equation, if I put in the different equations for I i can find the different heights? for example: for a hoop the equation would be h=(1/2mv^2 + 1/2(mr^2)(v/r)^2/mg This equation the mass would cancel out saying the height is? for a solid disk or cylinder: h=(1/2mv^2 +...

w=v/r so the equation would look like h=(1/2v^2 +1/2v^2)/g h=2(1/2v^2)/g I am unsure of how this equation will help relate the different masses to different height. I was also told that they don't all reach the same height because the incline is curved.

Homework Statement the five objects of various masses, each denoted m, all have the same radius. They are all rolling at the same speed as they approach a curved incline. Solid sphere - m = 1.0 kg Hollow Sphere - m = 0.2 kg Solid Cylinder - m = 0.2 kg Solid Disk - m = 0.5 kg Hoop - m = 0.2 kg...