Recent content by sarahmlipinsk

I found the force, and the force in the i direction, but not in the j...

I have this same problem, but I already got part a. Can someone please help me find part b?

Okay, I got it! Thank you so much for all of your help!

Okay, I think I got it. The only thing is,how do I find the final angular velocity?

No, I did not know how to do that... so then the final velocity would be equal to the final angular velocity times L?

I'm not quite sure. I said the moment of inertia for the rod is (1/12)ML^2 And the moment of inertia for the putty is mL^2

Oh, I see what you mean. I tried it that way, with no luck. I think my formula is just wrong.

Yes and yes.

The beginning part was supposed to be the moment of inertia and the second part is the omega.

And my initial kinetic energy was: (1/2)mv^2 Sorry about the clarity issues!

I had the final kinetic energy as: (1/2)(1/3)ML^2+mL^2(MvL)

I tried that. I compared the energy lost to the initial kinetic energy with the equation: KEi-KEf/KEi and then substituted my equations and got: (1/2mv^2-1/2*1/3ML^2+mL^2*mvL)/1/2mv^2 but that didn't work...

Can someone please help me solve this: http://wug.physics.uiuc.edu/cgi/courses/shell/per/phys111/ie.pl?11/IE_putty_plus_rod pivot putty question? Any help would be greatly appreciated!