Recent content by Satyr

Okay, your diagram somewhat clears the water for me. So the displacement is 7 because your initial location was 0 and your final location was 7...which would work for Xf - Xo also. However, when writing the motion your final position is the 10-3 because you come back over the path you've already...

Are you interchanging x and d for displacement? I'm still not following how Vavg=(deltaX)(deltaT) or V=(X2-X1)/(T2-T1) turned into: V=(X1-X2)/(T1+T2)

I have already done this problem enough times forwards and backwards to get the answer, so this is more of a theory question rather than help with homework. The equation for Vavg.=displacement/time or deltaX/deltaT. This equate to V=(X2-X1)/(T2-T1), correct? In working through a problem...

Thank you for clearing up my error in the first approach, I can see it now. As for your suggestion, I have tried that as well and it yields the same answer as my second approach. I feel like a huge fool right now. I found my mistake and, come to find out, my second approach was correct after...

Homework Statement The left ventricle of the heart accelerates blood from rest to a velocity of +26 cm/s. (a) if the displacement of the blood during acceleration is +2.0 cm, determine its acceleration (in cm/s^2). (b) How much time does blood take to reach its final velocity Homework...

right, I've figured that part i was wondering where I begin doing that? thanks

Homework Statement If lim x--> a of [f(x) + g(x)]=2 and lim x--> a of [f(x) - g(x)] = 1, then find lim x--> a f(x)g(x) Homework Equations Theorems of continuity The Attempt at a Solution Since I'm not quite sure if what I began with was right, it didn't yield me any type of a...

can someone at least take a look at number 4 for me? I think the others are okay, but I need to get 4 done tonight. thanks..

I think I solved question 5.

anybody have some time to give me a hand? lol

1) integral from -4 to 2 of 2/sqrt(x) dx I ended up with 4(sqrt2) - 4(sqrt-4); so I concluded it doesn't exist, correct? 2) integral (1+3x)x^2 This just seemed too simple to me, I ended up with f(x)=1/3x^3+3/4x^4+c, how's that look? 3) fifth derivative=0, find f(x); I ended up with...