Recent content by saucysaunders

Another way to complete Thanks! I understand where you're coming from now. I also managed to calculate the capacitor value using the resonance formula. Resonance -fo/r = 1 / 2π√LC ∴ C = (1/-fo/r)2 / ((2π)2 * L) C = (1/2500)2 / ((2)2 * 1.87) C = 2.167ηF

How did you find the equation for C Hi rude man. I've been looking at this question for a while now and am yet to see how you found the equation LC =1/ω2I assume you found it from 2πfL/R = 1/R x (√L/c) But I cannot confirm this is the case. I tried to find the capacitance using L/QR2 but I get...

Okay, I understand what I have done wrong now. I have now entered the info correctly into the calc, which gives me the following for I: I1 = 2.15E+00 +j1.23E+00 I2 = 7.69E-01 +j1.54E-01 I3 = -3.08E-01 +j1.54E+00 Now all I need to do to find the phase angle is convert to polar form. Thanks gneill!

I have made a pdf copy, the grey boxes are the editable boxes. The ones I filled out as per my equations. I have also tried re-arranging the circuit but it doesn't really help me.

This last comment is incorrect as for it to be balanced Z1/Z3 = Z2/Z4. So I3 should not be 0. What have I done wrong?

Actually I now think this is a bridge network. Meaning that current will not flow for I3 because Z2 and Z3 are equal. If Z2 and Z3 were not equal then there would be a current for I3. Am I correct?

From what I understand I now have to solve the simultaneous equations. My lecturer provided me with the attached 'complex matrix by decomposition' calculator, so I assume I should be using this to calculate the mesh currents. I have filled it out how I assume it is supposed to be done, however I...

I see my mistake now. I wrote the second line of pink completely incorrectly, I must have missed this in my proof reading. The current I2 and I3 are in the same direction also and should therefore be added rather than subtracted, correction below: Pink: = E - I2Z2 - (I2+I3)Z4 = E - (Z2+Z4)I2...

Homework Statement Apply mesh analysis to determine the magnitude and phase of the currents in the circuit of FIGURE 4, given the values in TABLE A Vs = 20 Vrms Z1 = 0 - j5 Ω Z2 = 5 + j5 Ω Z3 = 5 + j5 Ω Z4 = 0 - j10 Ω Z5 = 10 + j0 Ω Homework Equations KVL Simultanious...

Hi, I think from 2e onwards you need your calculator in the radians setting. This would give you an answer for when t=2.5 of 8.47amps. Could someone confirm my suspicions?

Torque in rope = 4.685 * 0.300 = 1.4055 Frictional Torque therefore = 1.4055 - 0.199935 = 1.21 Nm

Your wish is my command oh great one :P Thanks for the help!

I was confusing myself, by ignoring the fact that the wheel turning actually makes the tension in the rope less. It's all coming together now I think... Tension in the rope Ft = (0.5* -0.44) + (0.5*9.81) = 4.685N Torque in the rope = 4.685 * 0.212 = 0.993Nm So Frictional Torque = 0.993 -...

I understand acceleration is downwards, but using the neg figure would give tension as -5.127N Can you have a negative tension? Should I therefore be using this negative answer to work out the Rope torque?

Thanks for the reply! So, Tension in rope F = ma + mg = (0.5*0.44)+(0.5*9.81) = 5.127N The torque for the rope is therefore Trope = 5.127*0.212 = 1.087Nm Then, from my mistake at squaring earlier (thanks for pointing out): Net Torque = I*alpha = mk^2 *alpha = 0.135 * 1.481 =...