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Hi Guys, i guess this is the answer, I'm not sure! but? if someone has a comment reply pls.xxx tanθ = gy / gx = [ Gm / L2 + G M /2L2 sinθ ] / [ Gm /L2 + G M / 2L2 cosθ ] θ = tan-1 { [ Gm / L2 + G M / 2L2 sinθ ] / [ Gm /L2 + G M / 2L2 cosθ ]}