I=mr2 for a particle rotating about an axis, so unless I'm missing something the moment of inertia is simply I=mR^2 for Alice? (which is what I wrote in my previous post)
Okay thanks a lot. Well if we do it like that I get:
Kinetic energy for Alice:
T=0.5 m R`2 + 0.25 m R2 θ`2
Kinetic energy for the merry go round:
T = 0.5 m a2 θ`2 + 0.25 m a2 θ`2 = 0.75 m a2 θ`
Although I'm not confident with these answers. In my notes kinetic energy in a system is defined...
Homework Statement
Q) A child, Alice, on a playground merry-go-round can be modeled as a point mass m on a homogeneous horizontal disc of mass M and radius a. The disc rotates without friction about a vertical axis through its center. Alice clings to a straight railing that extends from the...
The question asks me to consider the system of differential equations:
\frac{dx}{dt} = 1 - 2x + x^2y
\frac{dy}{dt} = x-x^2y
It asks me to find the fixed point(s), and determine their stability, also to draw the phase plane.
So to find the fixed points, I set both equations equal to...