Recent content by savagefarmer

Sorry that reaction is wrong, it would be: C11H18N2O3 + H3O+ → C11H19N2O3+ + H2O

I just read about imides and di-imides, but I'm still clueless about the role they play in this. My guess was that the pentobarbital reacted with another H3O+ ion when a lot of HCl was added and the pH dropped further: C11H17N2O3- + H3O+ → C11H16N2O32- + H2O Does that make sense...

Ok sorry about that, I didn't realize that there would be a big overlap. I'll leave this up for now and hope for some pointers :)

Sorry, is there a policy against cross-posting on two entirely different forums?

Hello everyone, Today I witnessed the titration of a sodium pentobarbital solution with 0.1M HCl. At first, a lot of white precipitate was formed. When more HCl was added the white precipitate disappeared again completely. Now I am trying to figure out what is going on. As I understand it...