ok. the equilibrium position would occur when Fspring = Fefield
--> -K(x-s0) = QE
(x-s0) = (QE)/-k
plugged that into my first diff. eq., the K canceled and i got:
d^2t/dt^2 = (2QE)/m
Thanks so much for your guidance with part a!
From my understanding of Part B:
the first equilibrium position was at s0 which led to that diff eq. and now its asking for a different (smater i guess?) diff. eq. based on a new equilibrium position with the electric field "on"
I am confused...
Using F=ma I got:
Net force = Force of the electric field + Force of spring
F = -QE - K(x-S0) = ma
(x-s0) = the displaced length from equilibrium
that resulted in:
a = (-QE -Kx + K(s0))/m
Does that seem correct? can i set up the equation of motion from this?
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