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I used a kinematic equation of V[SIZE="1"]f = V[SIZE="1"]it + at to find the acceleration, which I got to be -2m/s2. I used this to get a tension of 6,240 N. You are right. I used the acceleration I found earlier in my equation N = m(g + a) and ended up with 390 N for the scale reading which...

I'm not sure if I approached this problem correctly and would like some assistance. Homework Statement An elevator with a total mass of 800 kg is moving downward at 6 m/s. It slows to a stop with constant acceleration in 3 seconds. a) Find the tension T in the supporting cable while the...