I used a kinematic equation of Vf = Vit + at to find the acceleration, which I got to be -2m/s2. I used this to get a tension of 6,240 N.
You are right. I used the acceleration I found earlier in my equation N = m(g + a) and ended up with 390 N for the scale reading which would be 39.8kg...
I'm not sure if I approached this problem correctly and would like some assistance.
Homework Statement
An elevator with a total mass of 800 kg is moving downward at 6 m/s. It slows to
a stop with constant acceleration in 3 seconds.
a) Find the tension T in the supporting cable while the...