Recent content by scotyard

  1. S

    Child in a family has at least 4sis and 2bros.

    is it correct now??
  2. S

    11 Days of Walking and Playing Badminton at My Friend's House

    thanks for guidance
  3. S

    11 Days of Walking and Playing Badminton at My Friend's House

    activity of 11 days = 11 Morn(M) and 11 evenings(E) i.e. walk 6 M AND badminton 5 Evenings. This leaves 5 M AND 6 E. OR walk 5M and Badminton 6 E. this leaves 6M and 5E- no activity.considering first posssibilty leads nowhere. But if we consider 2nd possibility; now, 11 M and 10 E did...
  4. S

    11 Days of Walking and Playing Badminton at My Friend's House

    If you do nothing in a morning, it doesn't say that you did nothing in the evening. ok.
  5. S

    Child in a family has at least 4sis and 2bros.

    the only possible combinations are: 4G+2B+1G = 7 CHILDREN (internally, each boy won't have 2brothers and sister will increase to 5) 4G+2B+1B = 7 CHILDREN. If we consider 1/4G+1/2B ?? But this time atleast 4 sis and 2 bro rqmnt will b completed. each child will have atleast 4 sis and 2 bro...
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    Child in a family has at least 4sis and 2bros.

    yeah, thatz wat is bugging me. question states a child and does not mentions the sex.
  7. S

    11 Days of Walking and Playing Badminton at My Friend's House

    Homework Statement I visited my friends home during my holidays.Our schedule went like this. We went for a walk in morning and played badminton in the evening. However due to the tiring nature of these, we did only 1 of them each day, i.e either walked or played Badminton. On some days we did...
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    Child in a family has at least 4sis and 2bros.

    Homework Statement Every child in a family has at least 4sis and 2bros. What is the least no. of children in the family? Homework Equations every child has 4 sis and 2 bros. The Attempt at a Solution so, atleast 6+1 children. so answer, i guess shud b seven?? can some1...
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