Recent content by seanmcgowan

thanks lonely pion. you and Doc Al helped me a LOT.

the answer would be 1.44*10^7

oh woops, its 10^9 ok so then it would be... 1.44*10^7

Coulomb's constant is 8.99*10^-9. at least, as far as my txt book is concerned.

ok the answer i got was 8*10^-4. then added it to itself and got 1.6*10^-3

oh ok, so ill use the 2*10^-6 in place of the 2 then, and 0.05 instead of 5 ill let you know what i get

um, yeah, i thought?

ok so for the answer i would: 8.99*10^-9 *( 2/25)= 7.19*10^-10 so then I add the two and get: 1.45*10^-9 is that it?

I used Kc*(q/r^2) for both of the particles. unfortunately the two cancel each other out. am i supposed to make one of them positive? or am i using the worng equation?

Im sorry i still don't get it. Do I use 5 cm rather than 10? and what is superposition? i didnt quite get your first defenition. are you saying to only use q1 in one equation, then q2 in the other? I am sorry i really have a tough time with this stuff.

Homework Statement Two point charges are 10.0 cm apart and have charges of 2.0 uC ( the u is supposed to be a greek symbol where the left side of the u is extended down) and -2.0 uC, respectively. What is the magnitude of the electric field at the midpoint between the two charges...

3.05 ohms. Thats right...right?

oh man, so I've had the answer all along! haha, thanks. one last question though, is there an easier way to find out what's parallel and what's series? or does that just come with practice?

Ok, I am probably going to start sounding real dumb here but I am not quite getting it. WHen figure out all of the parallel and series circuits, I come up with 18.45. If I subtract this from 21.50 i get 3.05. While this sort of fits, the missing resistor is in parallel right? and when I try to...

I thought that wa what the 21.50 ohms was about? isn't that the total resistance of all of the resistor's?