Recent content by seeker247

Thanks, once again, for the clarification. The whole problem, as I have discovered, was that I thought I could simply represent the result of the division[(x + 1) / (-x + 1)], which is "-1 + 2/(-x + 1)", by the power series "-1 + 2(sum x^n)" for n from 0 to infinity. Again, thanks.

If you can entertain one more follow up query, I'd like to know if the method of division you just explained is for special cases (as I've been taught to arrange the dividend and divisor in increasing powers of x when dividing polynomials)? ..

It all makes sense now: the quotient is the series. Thanks Mark44, and all who contributed. I'm glad I joined this forum.

If you could tell me how I may be doing this wrongly, I'd really appreciate it .. Also, I did try to evaluate the problem using Wolfram Alpha, and my answer showed up as the first of several "alternate forms" listed ..I've included the link...

There must be something I'm missing, since the result I get from computing the division "(1+x)/(1-x)" is "-1+2/(1-x)"; so that the power series representation is "-1 + 2(sum x^n)" for n from 0 to infinity... As a side note, I recognize that the 1st term of the correct representation is 1, but...

I'm very thankful for this tread, as I ran into the same problem as cheater1. I would like to point out, however, that while with Dick's method the 1st term of the series is 1, with Mark44's the first term appears to be -1. Any help in understanding why this is so would be greatly appreciated.