Recent content by seiferseph

ohh, i see, i forgot that to get that's how to get the entire function greater than 1, i get it now, thanks everyone!

Here is the problem I'm having some trouble with. The answer is fairly simple, it is the power of the e function. (the parabola x = y^2 + 1) I'm not sure how to get that, i could use some hints/help, thanks!

actually this would be a related rates problem then

one sec i'll post some stuff i was trying, and the question isn't optimization but I'm not really sure how to classify it

A particle is traveling along the postivie x-axis at a constant speed of 5 units per second. a) Where is the point when its distance from the point (0, 1) is increasing at a rate of 4 units per second? b) Where is the point when its distance from the point (0, 1) is increasing at a rate of...

Oh, i get it now, Thanks so much for all the help!

thats what someone told me, why is it (e^0.05 - 1) though? where did the -1 come from? i did try that and got the right answer, but i don't understand where it came from

i tried solving that, but I got a negative number, and the answer is should be 4.5 :confused:

isn't that just compound interset: P = P(o)*e^rt, where t = 1 and since you will be putting 15,500 + 1000 n (15500 + 1000n)*e^0.05 > 1000 ? because you will get 15500 + 1000n from selling, which you will put in the bank, and you want the profit made in one year to be greater than how...

I don't understand,what is wrong with what i was doing?

I'm having some trouble with this problem what i did was (15500 + 1000t)*e^0.05t > 1000 so basically, when the money you are making is greater than how much you would make by keeping the cards i know the first t = when you sell it, but what is the second t? that should be the amount of time...

just got it, thanks again for all this help! :smile:

there are 3 variables, d x and y, I'm not sure how to relate them into one. also, how do the equations relate? and thanks for the help, i got the other question!

i'm working on the first, after setting the derivative equal to zero, i get 6 h^2/3 / y^2/3 = 2 y^1/3 / h^1/3 before substituing in h = 16 - work and y = 6*work +6 how do i solve this equation?

Heres what i did for this one. find an equation relating work + math = 16 (total hours she has in a day). so math = 16 - work (i plug that into the equation for h) and for money, i have y = 6*work + 6 i plug this in as well and take the derivative. i get f ' = -4/3 *(6worrk + 6)^-2/3...